Suppose that a sample of gas occupies 119 mL
of volume at 25◦C and a pressure of 221 torr.
What would be the volume if the pressure
were changed to 647 torr at 25◦C?
This is boyle's law right? p1v1 = p2v2
Since I'm looking for v2 I rearranged it to be
v2 = p1v1 / p2
which is (221 torr) (0.119 L) / (647 torr)
(( I changed ml to L because that's what I've been taught in class ))
and then I got 0.04065 L ... I went so far out because the website we use to answer our questions on doesn't round but it says that I'm wrong. Can someone please tell me what I did wrong? Thanks
Based on the information you provided, you correctly identified that this problem can be solved using Boyle's Law. Boyle's Law states that the product of the initial pressure and volume is equal to the product of the final pressure and volume.
To solve for the final volume (V2), you rearranged the equation correctly:
V2 = (P1 * V1) / P2
Given:
P1 = 221 torr
V1 = 119 mL (converted to liters, V1 = 0.119 L)
P2 = 647 torr
Plugging in the values:
V2 = (221 torr * 0.119 L) / 647 torr
Simplifying this expression gives us:
V2 = 0.040865 L
You correctly calculated V2 as 0.04065 L (rounded).
It seems like there might be a minor rounding discrepancy between your answer and the expected answer. Please double-check if the website requires more precise rounding or if there is another factor that needs to be considered.