Math

Solve these simultaneous linear equations using elimination method :
3a = 2b + 1 and 3b = 5a - 3

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  1. first arrange them in "standard" form:
    3a - 2b = 1
    5a - 3b = 3

    1st times 3, ----> 9a - 6b = 3
    2nd times 2, ---> 10a - 6b = 6
    subtract them,
    a = 3
    sub back into 2nd
    3b= 5(3) - 3
    b = 4

    a = 3 , b = 4

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  2. Thanks for the solution . It's now clear to me.
    Though in the solution "first arrange in standard form ", it's to be
    3a-2b=1 and 3b-5a=-3 not 3b-5a=3.

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  3. gud job my friend

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