Which of the following shows the correct dissolution reaction for BaCl2?
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To determine the correct dissolution reaction for BaCl2, we need to understand the concept of ionic compounds and their dissolution in water. Ionic compounds are formed by the combination of positively and negatively charged ions. When an ionic compound dissolves in water, it breaks apart into its constituent ions.
The formula of barium chloride, BaCl2, suggests that it contains a barium ion (Ba2+) and two chloride ions (Cl-).
The dissolution of an ionic compound involves the dissociation of the compound into its constituent ions. In the case of BaCl2, it will dissociate into the Ba2+ cation and two Cl- anions.
Therefore, the correct dissolution reaction for BaCl2 is:
BaCl2(s) → Ba2+(aq) + 2Cl-(aq)
This equation represents the solid (s) form of BaCl2 dissolving in water (aq), resulting in the formation of aqueous (aq) Barium ions and chloride ions.