A rocket accelerates from rest at 17 m/s2 for
11 s.
How far will it cover during this time?
Answer in units of m.
How do I solve this? do I multiply 17m/s2 by 11 seconds??
d = 0.5a*t^2 = 0.5*17*11^2 =
1028.5
acceleration = 17m/s^2
take the anti derivative twice to get distance
P = 17/2t^2 + Ct + D
We know its at rest so it has no initial velocity, C = 0 and you can calculate it relative to a null position D = 0
Thus P = (17/2)t^2
plug in time of 11s
To find the distance covered by the rocket during this time, you need to use the equation of motion for uniformly accelerated motion:
distance = initial velocity × time + 0.5 × acceleration × time^2
In this case, the rocket starts from rest, so the initial velocity is 0 m/s. The acceleration is given as 17 m/s^2, and the time is 11 seconds.
Substituting these values into the equation, you get:
distance = 0 × 11 + 0.5 × 17 × (11)^2
Simplifying further:
distance = 0 + 0.5 × 17 × 121
distance = 0 + 1033.5
distance = 1033.5 m
Therefore, the rocket will cover a distance of 1033.5 meters during this time.