algebra

Suppose that the width of a certain rectangle is 1 inch more than one-fourth of its length. The perimeter of the rectangle is 32 inches. Find the length and width of the rectangle.

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  1. If the length is x, the width is 1 + x/4

    So, 2(x + 1 + x/4) = 32
    Now just solve for x and get the width.

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  2. 12

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  3. 31.25

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