Pre-Calculus HELP!

change the polar equation r=5/1+cos(theta) to rectangular form.

How do I do this? Thank you! :)

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  1. There's a nice discussion of this topic at

    http://laurashears.info/math122/unit4/polarAndParamFormsOfParabola/

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  2. recall:
    sinØ = y/r
    cosØ = x/r
    r^2 = x^2 + y^2

    I will assume you mean:
    r=5/(1+cos(theta) )
    r=5/(1+x/r)
    r + x = 5
    √(x^2 + y^2) = 5-x

    confirmation:
    http://www.wolframalpha.com/input/?i=%E2%88%9A%28x%5E2+%2B+y%5E2%29+%3D+5-x

    http://www.wolframalpha.com/input/?i=+polar+plot+r%3D5%2F%281%2Bcos%28theta%29+%29+from+-4%CF%80+to+4%CF%80

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  3. x^2 + y^2 = (5 - x) square right side since x^2 + y^2 = r^2
    x^2 + y^2 = 25 - 10x + x^2 the x^2 cancel out
    -x^2 -x^2'

    y^2 = 25 - 10x is the answer

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  4. r=5/1+cos theta

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