physics

1)In the special case of projectile, at what initial angle the range equals the maximum height?


If A is the launch angle measured from horizontal and V is the launch velocity, the maximum height achieved is
H = (1/2) (V^2/g) sin^2A
and the range is
R = 2 (V^2/g) sin A cos A.
You should be able to derive both of those formulas. If you need to see them derived, let us know.
Set R = H and solve for the angle A


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