Algebra 2

The Ferris wheel in the figure has a radius of 68 feet. The clearance between the wheel and the ground is 14 feet. The rectangular coordinate system shown has its origin on the ground directly below the center of the wheel. Use the coordinate system to write the equation of the circular wheel.
I am unsure how to set this up.
(x-0)^2+(y-14)^2=68?

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  1. The radius is 68, so the center is at y=68+14=82

    x^2 + (y-82)^2 = 68^2

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