If BD exceeds CD by 10 and

If BD=x^2 and CD = x + 4, compute x.

I tried:

BD = CD + 10

X^2 = (x+4)+10

x^2 = x+14

That's where I get stuck.

Do I convert to:

x^2 - x -14 = 0 ?

If so, how do I solve for x?

Thank you in advance for any assistance!

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  1. Assuming your math is ok as far as it went, have you not learned the quadratic formula? Use it, or solve by completing the square:

    x^2-x-14 = 0
    x^2-x = 14
    x^2 - x + 1/4 = 14 + 1/4
    (x - 1/2)^2 = 57/4
    x = 1/2 ±√(57/4)

    x = (1±√57)/2

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