physics

A speed skater moving across frictionless ice at 9.0 m/s hits a 5.3 m -wide patch of rough ice. She slows steadily, then continues on at 5.8 m/s. What is her acceleration on the rough ice? Express your answer using two significant figures.

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  1. V^2 = Vo^2 + 2a*d.

    V = 5.8 m/s.
    Vo = 9.0 m/s.
    d = 5.3 m.
    Solve for a. It will be negative.

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