# Trig

Evaluate the following expression:
sin(cos^-1(12/13))

tan(sin^-1(3/5))

I do not know what the inverse values would be...how would I work through this?

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1. This kind of problem works very well when you draw the pertinent triangle.

If cosθ = 12/13, you have a 5-12-13 triangle, so sinθ = 5/13

Similarly, sinθ = 3/5 gives you a 3-4-5 triangle, so tanθ = 3/4

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