For the following equation, how many grams of NO2 can be formed from 2.50 g of CuO mixed
with 0.500 L of NO gas at 25 C and 1.12 atm. ?
2 CuO (s) + NO (g)  Cu2O (s) + NO2 (g

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  1. This is a limiting reagent problem and you know that when amounts are given for BOTH reactants.
    Convert 2.50 g CuO to mols. mols = grams/molar mass = ?

    Convert 0.5 L NO gas to mols (n) using PV = nRT

    Using the coefficients in the balanced equation, convert mols CuO to mols of the product, NO2.
    Do the same with mols NO to mols NO2.

    It is likely that these two values for mols NO2 will not agree. The correct value in limiting regent problems is ALWAYS the smaller value and the reagent responsible for that value is the limiting reagent.

    Using the smaller value, convert that to grams. g = mols x molar mass = ?

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