Algebra

Suppose $A$ and $B$ are digits for which the product of the two-digit numbers $\underline{2A}$ and $\underline{AB}$ is 1971. Find the sum of $A$ and $B$.

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    Suppose A and B are digits for which the product of the two-digit numbers 2A and AB is 1971. Find A+B.

    2A*AB = (20+A)(10A+B) = 1971

    1971 = 3^3*73
    So, its only two-digit factors are
    27 and 73

    A+B=10

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