chemistry

Balance by partial methods

P4 + hno3 = h3po4+ no2+h2o

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  1. P4 + 16H2O ==> 4H3PO4 + 20e + 20H^+
    1H^+ + 1e + HNO3 ==> NO2 + H2O

    Multiply to keep the electrons equal and add the equations together. Finally, cancel ions/molecules common to both sides.

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  2. Its wrong

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  3. P4 + HNO3 ---------> H3PO4 + NO +H2O
    -> P4 + H2O -> H3PO4
    Then using hit and trial method
    P4 + H2O -> 4H3PO4 + 10[O]
    (addition of 10 atoms of oxygen i.e. nascent oxygen to make the equation balanced)
    -> HNO3 -> NO2 + H2O
    Again using hit and trial method
    2HNO3 +[O] -> 2NO2 + H2O
    (addition of 1 atom of nascent oxygen to make the equation balanced)
    NOTE : THE SAME EXTRA ATOM HAS TO BE MULTIPLIED ON BOTH THE SIDES AS PER THE SITUATION AND MUST BE CUT AT LAST
    Now adding both the equations to make a single balanced equation
    P4 + H2O -> 4H3PO4 + 10[O]
    + 2HNO3 +[O] -> 2NO2 + H2O } ×10
    ————————————————————
    P4 + 20HNO3 -> 4H3PO4 + 2NO + 9H2O
    AT last the oxygens and 1 water molecule get cancelled and the above answer remains
    Hence done......=)

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