bert is twice as old as cheng five yrs ago the sum of thier ages was 26 . how old is bert?
b = 2c
(b-5)+(c-5)=26
2c+c=36
c=12
So, bert is 24
alex and bert are friends and the sum of their ages is 60, nine years ago, alex twice as old as bert. how old is each
Let's set up equations using the given information.
Let's say the current age of Cheng is C years.
According to the question, Bert is twice as old as Cheng five years ago. So his age five years ago would be (2C - 5).
The sum of their ages five years ago was 26, so we can write the equation as: (C - 5) + (2C - 5) = 26.
Simplifying the equation, we have: C - 5 + 2C - 5 = 26.
Combining like terms: 3C - 10 = 26.
Adding 10 to both sides: 3C = 36.
Dividing both sides by 3: C = 12.
Therefore, Chen's current age (C) is 12 years.
To find out Bert's age, we can substitute C with 12 in the equation 2C - 5.
Bert's age = 2 * 12 - 5 = 24 - 5 = 19.
So, Bert is 19 years old.
To solve this problem, let's start by assigning variables to the unknown ages of Bert and Cheng.
Let's assume Bert's current age is B, and Cheng's current age is C.
First, we know that Bert is twice as old as Cheng.
So, we can write the equation: B = 2C ------ (Equation 1)
Next, it is given that five years ago, the sum of their ages was 26.
This means that five years ago, Bert's age was (B - 5), and Cheng's age was (C - 5).
So, we can write the equation: (B - 5) + (C - 5) = 26
Simplifying the equation, we get: B + C - 10 = 26 ------ (Equation 2)
Now, we have a system of two equations with two variables (Equation 1 and Equation 2). We can solve this system to find the values of B and C.
Let's solve this system of equations using substitution method:
From Equation 1, we have B = 2C.
Substitute B = 2C into Equation 2:
(2C) + C - 10 = 26
3C - 10 = 26
Add 10 to both sides:
3C = 36
Divide both sides by 3:
C = 12
Now that we have found Cheng's age, we can substitute this value back into Equation 1 to find Bert's age:
B = 2C
B = 2(12)
B = 24
Therefore, Bert is 24 years old.