chemistry

Standard Addition Question:

Serum containing Na+ gave a signal of 4.27 mV in an atomic emission analysis. Then 5.00 mL of 2.08 M NaCl were added to 95.0 mL of serum. This spiked serum gave a signal of 7.98 mV. Find the original concentration of Na+ in the serum.

I can't figure out the 0.113 M answer using the method poorly explained in the textbook.

  1. 👍
  2. 👎
  3. 👁
  1. Okay, I just figured out the answer and where my confusion came from. Correct me if I am wrong.

    x/0.104+0.950x = 4.27/7.98
    7.98x = 0.44408+4.0565x
    7.98x-4.0565x = 0.44408
    3.9235x = 0.44408
    x = 0.44408/3.9235
    x = 0.1131846566

    1. 👍
    2. 👎
  2. You know, of course, that I have no idea how your book explains it, poorly or otherwise. Here is how you do it but I don't know it's the same method your book uses. Personally, when I was in grad school we did it all by graphing it. Makes a lot more sense to me. You can do it mathematically but you need a graph to see what is going on. Do this and you can just sketch it on a sheet of paper.
    Draw the Y axis and X axis and mark the origin as zero concn. At the zero concn (which is what you're calling the sample), place a dot ON the Y axis and label it 4.056 mv.(That 4.27 was obtained in the pure sample; i.e., in the 95.00 mL sample before dilution. When you dilute it to 100 it will be 4.27 x (95/100) = 4.056) That's the zero point for the sample. How much Na^+ did you add? That's 2.08 M x 5.00/100 = 0.104M
    On the sketch, go out on the x axis some distance and place a dot at 0.104 M and move up on the Y axis some distance to 7.98 and place a dot there. Then you can sketch a straight line from the 4.056 mv mark at the zero point to the 7.98 mv point for 0.104M. That's your graph. You can see that 0.104 M added to the sample gave you 7.98-4.056 = 3.92 mv. So stick that into A = abc (and since the cell length is constant we can dispense with b--of course there is no cell in AES but it is a constant length) so 3.92 = ac.
    a = absorptivity constant = 3.92/0.104 = 37.72. Use that constant for a in the sample calculation.
    A = ac. 4.27 = 37.72c and
    c = about 0.113 M.
    If you do this on a sheet of graph paper and do it accurately, You extrapolate that straight line TO THE LEFT so it crosses the x axis to the left of the origin and you read the concn of the sample at that point.
    If this is not the same method as your book wants it done, you can write up the procedure from your book and I will interpret it and try to put it in words you can understand better than it is explained to you.

    1. 👍
    2. 👎
  3. OK. I see I didn't do it the same way but you can also see that my numbers are the same. That 3.92 is the absorptivity constant and the 4.056 actually was 4.0565 but I just dropped the last 5. The book method uses ratio/proportion while I tried to reason it out from the beginning. Hope this helped a little.

    1. 👍
    2. 👎
  4. Unfortunately, there is often more than one way to answer a textbook example. In class, it's one way (the quickest way), and in the textbook, it's another.

    The "quick" way is fine for tests and exams... but it is useful to me that I learn alternate methods as well.

    A step by step approach was lacking from the textbook explanation (my only complaint).

    Anyway; thanks for your suggestion. I will give your method a shot.

    1. 👍
    2. 👎
  5. We have two signals let say s1 and s2 where s1=4.27mV and s2=7.98mV
    Vol of the sample (Vs)=5.00mL
    Vol of dilution (Vx)=95.0mL
    Total vol(Vt)=100mL
    Conc of sample (Cs)=2.08m
    Consider the equation
    S1/s2=(CxVt)/(VxCx +VsCs)
    Where Cx is conc of Na
    By making Cx the subject then substitute the values to the equation you will get 0.113m

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    The steps to getting the answer. A certain metal oxide has the formula MO where M denotes the metal. A 39.46g sample of the compound is strongly heated in an atmosphere of hydrogen to remove oxygen as water molecules. At the end,

  2. chemistry

    What is the explanation for the discrete lines in atomic emission spectra?

  3. Physics

    A spacecraft in orbit around the moon measures its altitude by reflecting a pulsed 10Mz radio signal from the surface. If the spacecraft is 10km high what is the time between the emission of the pulse and the detection of the

  4. math

    A radio station's signal has a radius of 100 miles. If you drive at a constant speed of 40 miles an hour, nonstop, directly across the diameter of the signal, how long can you listen to the station before the signal fades?

  1. Biochem

    If .1ml of serum, 5ml of reagent and 4.9ml of distilled water are mixed together what is the dilution of the serum in the final solution

  2. Chemistry

    Which product is formed by beta emission from phosphorus -32? The atomic number of phosphorus is 15. A)28 Al 13 B)30 Al 13 C)32 S 16 D)32 P 15 E)33 P 15

  3. chemistry

    Which of the answers choices best describes John Dalton's contribution to atomic theory? he discovered to nucleus he gave future scientist a foundation for understanding how electrons move. he gave future scientist a foundation

  4. Chemistry help

    Average human blood serum contains 18 mg of K+ Calculate: a) the molar concentration for each of these species; use 1.00 g/mL for the density of serum. I have worked as of this (18 mg K+/100 mL)(1mL/1g)(1 mmol/39.10mg)(1g/1000mg).

  1. Chemistry

    A Serum taken from a patient being treated with lithium for manic-depressive illness was analyzed for lithium concentration. A reading of 291 units was obtained for the intensity of the 671 nm red emission line. Then 1.00 mL of a

  2. Analytical Chemistry

    Serum taken from a patient being treated with lithium for manic-depressive illness was analyzed for lithium concentration. A reading of 3.00xE2 units was obtained for the intensity of the 671 nM red emission line. Then 1.00 mL of

  3. CHEMISTRY HELP !!!!

    If a nucleus undergoes beta particle emission a. its atomic number decreases by four and its mass number decreases by two. b. its atomic number decreases by two and its mass number decreases by four. c. its atomic number increases

  4. Chem Check Please!!!

    1) Calculate the cell potential, at 25 C, based upon the overall reaction Zn2+(aq) + 2 Fe2+(aq) -> Zn(s) + 2 Fe3+(aq) if [Zn2+] = 1.50 x 10^-4 M, [Fe3+] = 0.0200 M, and [Fe2+] = 0.0100 M. The standard reduction potentials are

You can view more similar questions or ask a new question.