I'm having trouble understanding rate laws and manipulating them.
So, for example, the rate law is rate= k[CO2][O3]. I was taught, maybe if I am just forgetting some pieces(been awhile), if I were to triple/double the partial pressure of CO2/O3, the rate of that element would be tripled/doubled since it's in the first power.
But what would happen if it was in the 2nd power? Would it be sixle(6)? Also, is saying ion concentration change the way the rate law occurs, or is it in the same ball park as saying partial pressure in a problem?
I think the answer to all of your questin is yes.
If you double the pressure then the volume is halved and the concentration is doubled. Right? So just figures p and c are the same for this. And yes, in your example they are tripled and doubled because the power of each is 1. So 3^1 is 3 and 2^1 is 2. Right?
Now if it were a second order in CO2 and third order with O3, say like this, rate = k(CO2)^2*(O3)3, then
if you double CO2 rate will be 2^2 or 4 time. If you double O3 it will be 2^3 = 8 times. If you double CO2 AND double O3 it will be 2^2 x 2^3 = 4*8 = 32 times.
Oh, I see, thanks!
Just for some clearing: The 3 you used in your answer was the "if I were to triple" 3 right? Or did you take that from O3?
I made a typo in that response and that may have confused you. However, after starting that sentence with 'Now if it were a second ....." I never tripled anything. I doubled CO2 and doubled O3.
i SHOULD have written, if the equation were rate = k(CO2)^2(O3)^3. Then just replace CO2 with x and O3 with y and the equation becomes rate = k(x)^2(y)^3. Then doubling x increases rate by 4 and doubling y increases it by 8 while doubling BOTH x and y increases the rate by 32 times. The 3 you see in O3 never entered into any of this discussion. Does that clear things up? Note that the typo was (O3)3 and it should have been written (O3)^3.
No I meant above that part in the 3^1<--Where was this 3 from?
I've copied this from above.
And yes, in your example they are tripled and doubled because the power of each is 1. So 3^1 is 3 and 2^1 is 2. Right?
So the 3^1 comes because of your tipled/doubled part and the 2^1 comes from your tripled/doubled part. And the 3 in the O3 is not part of the discussion. My assumption was that tripled meant you tripled CO2 and doubled meant you doubled O3.