calculus

If dy=(2x+1)dx and y=7 when x=1, find the value of y when x=3.

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  1. dy = 2 x dx + dx

    y = x^2 + x + c
    7 = 1 + 1 + c so c = 5
    and
    y = x^2 + x + 5
    when x = 3
    y = 9 + 3 + 5
    = 17

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