How many moles of Ag2CrO4 will be produced from 6 moles of AgNO3?
6molAgNO3*molAg2CrO4/molAgNO3=molAg2CrO4
You need to use coefficients from chemical equation, you didn't give one, and plug coefficients into mol ration : mol/mol
Anonymous points out that you don't have an equation; however you can use an ionic equation of
2Ag+ + CrO4^2- ==> Ag2CrO4
Assuming you have enough chromate to use all of the AgNO3, you can produce 6 mols AgNO3 x (1 mol Ag2CrO4/2 mols AgNO3) = ?
2AgNO3 + Na2CrO4 ==> Ag2CrO4 + 2NaNO3
To determine the number of moles of Ag2CrO4 produced from 6 moles of AgNO3, we need to consider the balanced chemical equation for the reaction between these two compounds.
The balanced equation for the reaction is:
2 AgNO3 + Na2CrO4 → Ag2CrO4 + 2 NaNO3
From the equation, we can see that 2 moles of AgNO3 react to produce 1 mole of Ag2CrO4.
Therefore, if we have 6 moles of AgNO3, we can calculate the number of moles of Ag2CrO4 produced by using the ratio between the two compounds in the balanced equation:
6 moles AgNO3 × (1 mole Ag2CrO4 / 2 moles AgNO3) = 3 moles Ag2CrO4
So, from 6 moles of AgNO3, 3 moles of Ag2CrO4 will be produced.