If 25ml of 3M HNO3 AND 75ml of 4M HNO3 ar
What is your question?
Probably you want to know the (H^+).
mols of the 3M HNO3 = M x L = ?
mols of the 4M HNO3 = M x L = ?
M of the mixture is M = total mols/total L
If you want to know the pH it is pH = -log(HNO3)
It seems like your question got cut off. However, based on the information provided, I assume you want to know the concentration of the resulting solution when 25 mL of 3M HNO3 and 75 mL of 4M HNO3 are mixed together.
To determine the resulting concentration, you need to use the principles of solution dilution. When two solutions are mixed together, the resulting solution's concentration can be calculated using the following formula:
C1V1 + C2V2 = C3V3
Where:
C1 = concentration of the first solution
V1 = volume of the first solution
C2 = concentration of the second solution
V2 = volume of the second solution
C3 = resulting concentration
V3 = resulting volume (which is the sum of V1 and V2)
From the information given, we have:
C1 = 3M
V1 = 25mL
C2 = 4M
V2 = 75mL
First, we need to convert the volumes to the same units, so let's convert mL to L:
V1 = 25mL = 0.025L
V2 = 75mL = 0.075L
Substituting the values into the formula:
(3M)(0.025L) + (4M)(0.075L) = C3(0.025L + 0.075L)
Simplifying the equation:
0.075M + 0.3M = C3(0.1L)
0.375M = 0.1C3
Finally, solving for C3:
C3 = 0.375M / 0.1L
C3 = 3.75M
Therefore, the resulting concentration of the mixed solution is approximately 3.75 M.