Math
In a certain industry, 35% are female, 72% work full time and 18% are females who work full time.
Probability that a randomly chosen employee is female and does not work full time?
A: 0.18
B: 0.54
C: 0.11
D: 0.17
E: 0.098
I got 0.098 because I did 0.35 * 0.28. The actual answer is D. I cannot figure out how to get 0.17. Can you guide me how to get it? Or I might be correct and the answer is wrong
asked by
G

Imagine an industry with 100 employees.
35 of them are female. 18 of them work full time. So the rest works part time.
35  18 = 17
17/100 = 0.17
So, 0.17posted by Anonymous
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