Math

In a certain industry, 35% are female, 72% work full time and 18% are females who work full time.

Probability that a randomly chosen employee is female and does not work full time?
A: 0.18
B: 0.54
C: 0.11
D: 0.17
E: 0.098


I got 0.098 because I did 0.35 * 0.28. The actual answer is D. I cannot figure out how to get 0.17. Can you guide me how to get it? Or I might be correct and the answer is wrong

asked by G
  1. Imagine an industry with 100 employees.
    35 of them are female. 18 of them work full time. So the rest works part time.

    35 - 18 = 17

    17/100 = 0.17

    So, 0.17

    posted by Anonymous

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