What is the volume, in L, occupied by 1.20 moles of C2H6 gas at a temperature of 125oC and at a pressure of 1.55 atm?
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How do I set up the problem?
PV = nRT and solve for V in L.
To calculate the volume occupied by a gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure of the gas (in atm)
V = volume of the gas (in L)
n = number of moles of the gas
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature of the gas (in Kelvin)
First, we need to convert the temperature from Celsius to Kelvin by adding 273.15:
T = 125 + 273.15 = 398.15 K
Next, we can rearrange the ideal gas law equation to solve for V:
V = (nRT) / P
Substituting the given values:
V = (1.20 moles x 0.0821 L·atm/(mol·K) x 398.15 K) / 1.55 atm
V = 39.1572 L
Therefore, the volume occupied by 1.20 moles of C2H6 gas at a temperature of 125oC and a pressure of 1.55 atm is approximately 39.16 L.