Algebra1

what are the coordinates of the vertex of the parabola defined by:
f(x)=9(x-8)+8
I'm confused on how to solve this. Help pls

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asked by kesha
  1. Need an x^2 somewhere
    perhaps
    y = 9 (x-8)^2 + 8
    or something?

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    posted by Damon
  2. If it is indeed
    y = 9 (x-8)^2 + 8
    then
    y = 9 (x^2 - 16 x + 64) + 8
    y = 9 x^2 - 144 x + 576 + 8
    y = 9 x^2 - 144 x + 584
    then
    x^2 - 16 x + 64 8/9 = y/9

    x^2 - 16 x = y/9 -64 -8/9

    x^2 - 16 x + 64 = y/9 -64 -8/9 + 64

    (x-8)^2 = y/9 -8/9 = (1/9)(y-8)

    vertex at (8,8)

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    posted by Damon
  3. of course we could have short cut that by saying
    9 (x-8)^2 = y-8
    then
    (x-8)^2 = (1/9)(y-8)
    but best do the whole completing the square process.

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    posted by Damon

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