# Algebra 1 honors

Mr. Oliver invested a total of \$6400, part at 9% per year and the remainder at 8% per year. At the end of 2 years and 6 months, he had earced a total investment of \$1380 in simple interest. How much ded he invest at each rate.

I have to come up with the equation.

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1. .09x+.08x(30)= \$1380 + \$6400 = ?

......i think/hope that this is right....

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posted by bex
2. Bex, I have to have 2 different numbers. I have to find out how much he invested at each individual rate.
I have .09x + .08(6400 - x)=1380.

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posted by Kearse
3. sorry.im not very good at algebra =[

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posted by bex
4. .09x+.08x(30)= \$1380 + \$6400 =

(Multiply .08 X 30 = 2.4)

.09x + 2.4x = 7780
3.3x = 7780

3.3x \$7780
---- = -----
3.3 3.3

x = \$2357.57

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posted by Algebrologist
5. i need 9 factors of 4x squared

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posted by sexi kitten

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