# physics

A pair of glasses are dropped from the top of a 32.0 m high stadium. A pen is dropped from the same position 2.00 s later. How long does it take for the glasses to hit the ground? How high above the ground is the pen when the glasses hit the ground? (Disregard air resistance)

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1. Find the time of fall by using:
y = (1/2)gt^2
(y is given and g = 9.8m/s^2, Solve for t)

When the glasses hit the ground, the pen has been falling for (t-2.00s). The height above the ground of the glasses is:
32.0m - (1/2)g(t-2)^2

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posted by GK
2. Correction to the previous answer:
"The height above the ground of the glasses is:
The height above the ground of the pen is:
32.0m - (1/2)g(t-2)^2

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posted by GK
3. 2 m

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posted by Gigjv
4. 25.6

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posted by merges
5. 1.5 m

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posted by Steve

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