physics

A pair of glasses are dropped from the top of a 32.0 m high stadium. A pen is dropped from the same position 2.00 s later. How long does it take for the glasses to hit the ground? How high above the ground is the pen when the glasses hit the ground? (Disregard air resistance)

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  2. ๐Ÿ‘Ž 0
  3. ๐Ÿ‘ 101
asked by Dee Dee
  1. Find the time of fall by using:
    y = (1/2)gt^2
    (y is given and g = 9.8m/s^2, Solve for t)

    When the glasses hit the ground, the pen has been falling for (t-2.00s). The height above the ground of the glasses is:
    32.0m - (1/2)g(t-2)^2

    1. ๐Ÿ‘ 0
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    posted by GK
  2. Correction to the previous answer:
    "The height above the ground of the glasses is:
    32.0m - (1/2)g(t-2)^2" should read:
    The height above the ground of the pen is:
    32.0m - (1/2)g(t-2)^2

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    posted by GK
  3. 2 m

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    2. ๐Ÿ‘Ž 0
    posted by Gigjv
  4. 25.6

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    2. ๐Ÿ‘Ž 0
    posted by merges
  5. 1.5 m

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    2. ๐Ÿ‘Ž 0
    posted by Steve

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