a man travelled a distance of 22 km in 1 hour, partly in a car at a speed of 30 km/hour and partly on a motorcycle at 18 km/hour . find the distance travelled by him in the car.

Given, Total distance= 22 kms.

We know that,
Distance = Speed x Time
Suppose, time taken to travel by car is T mins.
So According to ques -
22 = 30T + 18(1-T)
T= 1/3
Now, distance by car = 30 x 1/3
= 10 kms.

Why -1?

To find the distance traveled by the man in the car, we can use the concept of average speed.

Average speed is calculated by dividing the total distance traveled by the total time taken. In this case, the man traveled a total distance of 22 km in 1 hour.

Let's assume the distance traveled by the man in the car is 'x' km. Therefore, the distance traveled by the man on the motorcycle would be (22 - x) km, as the total distance is 22 km.

Now, we can use the formula for average speed: Average Speed = Total Distance / Total Time

The time taken by the man in the car can be calculated as x km divided by the car's speed of 30 km/h. Similarly, the time taken by the man on the motorcycle would be (22 - x) km divided by the motorcycle's speed of 18 km/h.

So, the equation becomes:

( x / 30 ) + (22 - x) / 18 = 1

To find the value of 'x', we can solve this equation.

Multiplying through by 30 * 18 gives:

18x + 30(22 - x) = 540

Expanding and simplifying:

18x + 660 - 30x = 540

Combine like terms:

-12x + 660 = 540

Subtract 660 from both sides:

-12x = -120

Divide by -12:

x = 10

Therefore, the man traveled a distance of 10 km in the car.

The distance traveled by the man in the car is 10 km.

23 1|10

I don't no

distance = rate x time + rate x time

22 = 30(x) + 18 (1-x)
22 = 30x + 18 -18x

x = time of car

Find and multiply it by 30 to find distance traveled in the car.