Treatment with sodium borohydride converts aldosterone A in to an optically inactive alditol. Ruff degradation of A from B, whose alditol is optically inactive. Ruff degradation of B from D - glycerol dehydration. Identify A and B.please give satisfactory answer
To answer this question, we'll need to move step by step through the given information.
1. Treatment with sodium borohydride converts aldosterone A into an optically inactive alditol.
This means that when aldosterone A is treated with sodium borohydride, it undergoes a chemical reaction and forms an alditol that is optically inactive.
2. Ruff degradation of A from B, whose alditol is optically inactive.
Ruff degradation is a chemical process that breaks down organic compounds. In this case, Ruff degradation is used to convert aldosterone A into another compound called B. Additionally, we are told that the alditol derived from B is optically inactive, meaning it does not rotate the plane of polarized light.
3. Ruff degradation of B from D - glycerol dehydration.
This sentence states that the compound B, which was derived from A, can be further transformed into another compound, D. The process used here is glycerol dehydration.
From the information given, we can deduce the following relationships:
- Aldosterone A is converted into an alditol, which is optically inactive.
- Aldosterone A can be transformed into compound B through Ruff degradation.
- Compound B can undergo glycerol dehydration to form compound D.
Unfortunately, based solely on this information, we cannot identify the specific compounds A and B. We would need additional data or chemical structures to make a conclusive identification.