Jane spends 1/3 of her money on snacks and 2/5 on a book. She remained with $60.00. how much money had Jane.?
use branching method or model. I think the answer is $90. 1u is 15.
I am not so sure.
or basic algebra ....
let her total amount of money be x
x - (1/3)x - (2/5)x = 60
multiply all terms by 15
15x - 5x - 6x = 900
4x = 900
x = 225
Jane had $225
check:
snacks = (1/3)(225) = 75
book = (2/5)(225) = 90 , expensive book!
amount left = 225-75-90 = 60
To solve this problem, we need to set up an equation based on the information given.
Let's assume that Jane had "x" amount of money initially.
According to the given information, Jane spends 1/3 of her money on snacks and 2/5 on a book.
The amount of money Jane spent on snacks is (1/3) * x.
The amount of money Jane spent on a book is (2/5) * x.
The remaining amount of money Jane has is $60.00.
Therefore, we can set up the equation:
x - [(1/3) * x + (2/5) * x] = $60.00
We simplify the equation:
x - [(1/3) * x + (2/5) * x] = $60.00
x - [(5/15) * x + (6/15) * x] = $60.00
x - [(11/15) * x] = $60.00
Multiplying both sides of the equation by 15 to get rid of the denominator, we have:
15x - 11x = $900.00
Simplifying the equation:
4x = $900.00
To solve for x, we divide both sides of the equation by 4:
x = $225.00
Therefore, Jane had $225.00 initially.