A brick mass of 4.5 kg is thrown rertical into the air the brick leave the hand at a velocity of 10 m/s find the kinetic energy the moment it leave the hand?
0.45 is the answer but I am not sure.
35678
To calculate the kinetic energy of an object, you can use the formula:
Kinetic Energy = 1/2 * mass * velocity^2
Given that the mass of the brick is 4.5 kg and the velocity at the moment it leaves the hand is 10 m/s, you can substitute these values into the formula:
Kinetic Energy = 1/2 * 4.5 kg * (10 m/s)^2
First, square the velocity:
Kinetic Energy = 1/2 * 4.5 kg * 100 m^2/s^2
Next, multiply the mass and the squared velocity:
Kinetic Energy = 0.5 * 4.5 kg * 100 m^2/s^2
Kinetic Energy = 225 kg m^2/s^2
Therefore, the kinetic energy of the brick at the moment it leaves the hand is 225 Joules (J).