b^2-22b+57
I am not sure but I got b(b-22)+57
Looks right to me.
No, the answer should be:
b^2-22b+57 =
(b - 3)*(b - 19)
To find the correct factorization of the quadratic expression b^2-22b+57, you can use the quadratic formula or factorization by grouping. Let's use the latter method.
Start by looking for two numbers whose product is 57 and whose sum is -22, the coefficient of the middle term. In this case, the numbers are -3 and -19.
Next, rewrite the middle term (-22b) as the sum of these two numbers:
b^2 - 3b - 19b + 57
Now, group the terms and factor by common factors:
(b^2 - 3b) - (19b - 57)
Factor out the common factors from each group:
b(b - 3) - 19(b - 3)
Now, you can see that there is a common factor, (b - 3), that can be factored out:
(b - 3)(b - 19)
So, the correct factorization of b^2-22b+57 is (b - 3)(b - 19).