A physicist converted 2 kg of water at 37 degrees celcius to steam at 100 degrees celcius. Assuming no heat is lost, calculate the amount of energy needed to heat to 100 degrees celcius.

To calculate the energy needed to heat the water to 100 degrees Celsius, we can use the equation:

Q = mcΔT

Where:
Q is the energy transferred (in Joules)
m is the mass of the substance (in kg)
c is the specific heat capacity of the substance (in J/kg·°C)
ΔT is the change in temperature (in °C)

First, let's determine the energy required to heat the water from its initial temperature of 37 degrees Celsius to its boiling point of 100 degrees Celsius.

The specific heat capacity of water (c) is approximately 4.18 J/g·°C, or 4,180 J/kg·°C.

Given:
Mass of water (m) = 2 kg
Initial temperature (T1) = 37 °C
Boiling point temperature (T2) = 100 °C

Calculating the temperature difference:
ΔT = T2 - T1
ΔT = 100 °C - 37 °C
ΔT = 63 °C

Now, we can calculate the energy required to heat the water:

Q = mcΔT
Q = (2 kg) × (4,180 J/kg·°C) × (63 °C)
Q ≈ 527,520 J

Therefore, approximately 527,520 Joules of energy are required to heat 2 kg of water from 37 degrees Celsius to 100 degrees Celsius.

To calculate the amount of energy needed to heat the water from 37°C to 100°C, we can use the formula:

Q = mcΔT

where:
Q is the amount of heat transfer (energy),
m is the mass of the substance being heated,
c is the specific heat capacity of the substance,
ΔT is the change in temperature.

For water, the specific heat capacity (c) is approximately 4,186 J/kg·°C.

Given:
m = 2 kg (mass of the water)
ΔT = (100°C - 37°C) = 63°C (change in temperature)

Let's substitute these values into the formula to find the energy needed:

Q = (2 kg) × (4,186 J/kg·°C) × (63°C)

Calculating this equation gives us:

Q = 527,532 J

Therefore, the amount of energy needed to heat 2 kg of water from 37°C to 100°C is 527,532 Joules.

Yes, your wording indicates that you need help.

You not only have to heat the water to 100 deg C
You have to BOIL IT as well !
so
look up the specific heat of water, call it C
then LOOK UP THE HEAT OF VAPORIZATION of water.

then
heat in = 2 * specifc heat * (100-37)
+
2 * heat of vaporization of 1 kg of water

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