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Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that sin (1/x)=0 sin (1/x)=1 sin (1/x)=1 Is sin sin (1/x)=0 and sin (1/x)=1 does not exist. What is sin (1/x)=1 then.
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Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1
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Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1
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