Math

How many real number solutions does the equation have? y=3x^2-5x-5

A)one solution
B)two solutions
C)no solutions
D)infinitely many solutions

I can't figure this question out. Any help would be amazing.

asked by Sasha
  1. make a sketch of the graph using
    x = -1,0,1,2,3

    posted by Reiny
  2. I still don't get it... Should I graph them as points? Because when I graph just x=-1 and ect... I get straight lines going up and down at the following points, (-1,0), (0,0),(1,0),(2,0),(3,0).

    posted by Sasha
  3. Is it no solutions?

    posted by Sasha
  4. No, the answer is two solutions, Correct?

    posted by Sasha
  5. your first response tells me you are having difficulties evaluating a function for a given x

    x = -1 , y = 3(-1)^2 - 5(-1) - 5 = 3+5-5 = 3
    so the point is (-1,3)
    x = 0 , y = -5 , so the point is (0,-5)
    x = 1 , y = 3(1)^2 -5(1) - 5 = -7
    so the point is (1,-7)
    x = 2 , y = -3 , point is (2,-3)
    x = 3, y = 7 , point (3,7)

    without even looking at the graph and knowing that it is a parabola opening upwards, I can see that the graph from (-1,3) to (0,-5) must have crossed the x-axis, and from (2,-3) to (3,7) must have crossed it a second time,
    so, yes, there are two solutions.

    Looks like you are just guessing.

    posted by Reiny

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