For each quadratic function, find the axis of symmetry of its graph.
y=3x^2-6x+4
To find the axis of symmetry of a quadratic function, you can use the formula x = -b/2a, where the quadratic function is in the form ax^2 + bx + c.
For the given quadratic function y = 3x^2 - 6x + 4, we can identify that a = 3 and b = -6.
The formula for the axis of symmetry is:
x = -b/2a
Substituting the values of 'a' and 'b' into the formula, we have:
x = -(-6)/(2 * 3)
x = 6/6
x = 1
Therefore, the axis of symmetry for the given quadratic function y = 3x^2 - 6x + 4 is x = 1.
To find the axis of symmetry of a quadratic function, you can use the formula:
x = -b / (2a)
In this case, the quadratic function is y = 3x^2 - 6x + 4. By comparing it with the standard quadratic function form y = ax^2 + bx + c, we can determine that our values of a, b, and c are:
a = 3
b = -6
c = 4
Now, plug these values into the formula to find the axis of symmetry:
x = -(-6) / (2 * 3)
x = 6 / 6
x = 1
Therefore, the axis of symmetry of the graph of the given quadratic function y = 3x^2 - 6x + 4 is x = 1.
complete the square ....
y = 3(x^2 - 6x ....) + 4
= 3(x^2 - 6x + 9 - 9) + 4
= 3( (x-3)^2 - 9) + 4
= 3(x-3)^2 - 27 + 4
= 3(x-3)^2 - 23
I trust you can take it from here.