1. The batteries in a digital alarm clock provide a terminal voltage of 9 V. What is the potential difference across the entire clock current?
A. 4.5 V
B. 18.0 V
C. 9.0 V
D. 6.0 V
**C is my answer
Am I correct? Thanks!!
Mine too :)
Of course that is just across the clock circuit, not including the battery itself.
If you do a complete loop around any circuit the total potential changes add up to zero. That is fundamental to the meaning of potential of any sort, voltage, gravitational, elevation etc.
In other words read carefully. This might be a trick question.
To determine the potential difference across the entire clock circuit, we need to understand how multiple components in a circuit are connected.
In the case of an alarm clock, the batteries are connected in series, which means their voltages add up. Since there is only one battery, its voltage is the total voltage across the clock circuit.
Given that the battery provides a terminal voltage of 9 V, we can conclude that the potential difference across the entire clock circuit is indeed 9 V.
Therefore, your answer (C) 9.0 V is correct.