There eight girls competing in an ice=skating competition. In how many ways can they finish in first, second and third place?
366
1,680
2,016
40,320
I think it is 2,016
d
a
c
a
I PROMISE
IF YOU DON'T BELIEVE ME TYPE QUESTION 4 INTO JISKHA AND THE ANSWERS WILL POP UP
No,
8 different girls can finish first,
for each of those 7 can finish second
and for each of those 6 can finish third, so
8*7*6 = 366
Fffff some people help and some people don't. Though I am here right now for assistance I can receive the awnser and figure out how they got it. Sorry if I sound rude but life isn't perfect, nothing can go your way. People can do whatever they want. They make their own decisions not what other people think...
JAZZZZMIN is correct. :)
1. D
2. A
3. C
4. A
100
Yes, @JAZZZZMIN is 100% correct! The answers are:
1. D
2. A
3. C
4. A
100% correct! Your Welcome! :)
JAZZZZMIN is correct
JAZZZZMIN is correct
Thank you JAZZZMIN, i write down the answers but still find out how to do the work so i can learn it.
Jazzmin and Hal are right
ITS D A C A TO GET 4/4 JAZZZMIN IS RIGHT
agreed Memed :P its not like they're people who know instantly whether your answer is correct or not. they just go based off of what they were taught in school. some people on this website need to notice this.
Also JAZZZZMIN, and Hal are correct for Unit 6, Lesson 6: Permutations, 7B Math
M🦋🦋
Since we're wrapping up the school year, just wanna say thanks to everyone for all the help!~
sadly I might not be back online next year. hopefully i am tho~
Have a great summer everyone~
JAZZZZIMEN IS CORRECT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
jazzzzmin is correct!!
thxx got 100%
I still didn't understood where's the solution?
1. How many ways can 6 books: 720
2. Eight girls ice-skating: 336
3. President/Vice out of 12: 132
4. 7 students lined up: 5,040
1. The number of ways that 6 books can be arranged is `6! = 6 x 5 x 4 x 3 x 2 x 1 = 720` ways.
2. The number of ways that 8 girls can finish in first, second, and third place is `8 x 7 x 6 = 336` ways.
3. The number of ways to select a president and vice president from 12 candidates is `12 x 11 = 132` ways.
4. The number of ways that 7 students can line up is `7! = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5,040` ways.