can someone explain to me also how to do addition with equations.
Solve the system by addition
5x-3y=13
4x-3y=11
its easy try properly
It's not easy
"It's not easy"
Then how come I found the answer:
x = 2; y = -1, in just five seconds by just looking at the equations? :)
How did you come up with those answers.
To solve the system of equations using addition, you need to eliminate one variable by adding or subtracting the two equations. Here's how you can do it step by step:
1. Arrange the equations in a way that aligns the variables and constants.
5x - 3y = 13
4x - 3y = 11
2. Identify which variable you want to eliminate. In this case, let's eliminate the "y" variable. To do this, multiply the second equation by a constant such that the coefficients of "y" in both equations become the same.
5x - 3y = 13
(4x - 3y) * (5/4) = 11 * (5/4)
(4x - 3y) * (5/4) = 55/4
3. Simplify both equations.
5x - 3y = 13
(5/4)(4x) - (5/4)(3y) = 55/4
5x - (15/4)y = 55/4
4. Now, add the two equations together to eliminate the "y" variable and solve for "x".
(5x - 3y) + (5x - (15/4)y) = 13 + (55/4)
10x - (3+15/4)y = 13 + (55/4)
10x - (12/4 + 15/4)y = 52/4 + 55/4
10x - (27/4)y = 107/4
5. Simplify the equation further.
10x - (27/4)y = 107/4
6. Solve for "x" by isolating the variable on one side of the equation.
10x = 107/4 + (27/4)y
10x = (107 + 27y)/4
x = (107 + 27y)/40
7. Now, substitute the value of "x" back into one of the original equations to solve for "y".
5x - 3y = 13
5((107 + 27y)/40) - 3y = 13
(535 + 135y - 120y)/40 - 3y = 13
(535 - 15y)/40 = 13
535 - 15y = 520
-15y = -15
y = 1
8. Finally, substitute the value of "y" back into one of the original equations to solve for "x".
5x - 3(1) = 13
5x - 3 = 13
5x = 16
x = 16/5
Therefore, the solution to the system of equations is x = 16/5 and y = 1.