What value of x makes the equation true?
(x-16)4/3=81
I have a feeling judging by the numbers that he meant:
(x-16)^(4/3) = 81
x - 16 = 81^(3/4)
x - 16 = 27
x = 43
Must show all work.
if im reading this right, multiply both sides by 3 to cancel it from the left and distribute 4 into (x-16) to get 4x-64. add 64 to both sides and divide the final number on the right by 4 to get x
To solve for x in the equation, we need to isolate x on one side of the equation. Here's how you can do it step by step:
1. Start by multiplying both sides of the equation by 3/4 to get rid of the fraction:
(3/4) * (x - 16) * 4/3 = 81 * 3/4
Simplify:
(x - 16) = 243/4
2. Now, we can solve for x by adding 16 to both sides of the equation to isolate x:
(x - 16) + 16 = 243/4 + 16
Simplify:
x = 243/4 + 64/4
3. Combine the fractions:
x = (243 + 64)/4
x = 307/4
Therefore, the value of x that makes the equation true is x = 307/4 or 76.75.