a bullet fired with a speed of 150 m/sec from car whose velocity is 25/3 m/sec to car next to it whose velocity is 50 m/sec.what is velocity of bullet with respect to ground?
To find the velocity of the bullet with respect to the ground, we need to add the velocities of the bullet with respect to the car and the car's velocity with respect to the ground.
Given:
Velocity of the bullet with respect to the first car (v1) = 150 m/s
Velocity of the first car with respect to the ground (v2) = 25/3 m/s
Velocity of the second car with respect to the ground (v3) = 50 m/s
Now, we can calculate the velocity of the bullet with respect to the ground (v4):
v4 = v1 + v2 + v3
Substituting the given values:
v4 = 150 m/s + 25/3 m/s + 50 m/s
To simplify the addition, we need to convert 25/3 m/s to a decimal:
25/3 m/s = 25/3 × 1 m/s ≈ 8.333 m/s
v4 = 150 m/s + 8.333 m/s + 50 m/s
Now, add the velocities:
v4 = 150 m/s + 8.333 m/s + 50 m/s
≈ 208.333 m/s
Therefore, the velocity of the bullet with respect to the ground is approximately 208.333 m/s.