# maths

the sides of a rectangle are given in centimeters up length 4x+3 down length x+ 6y,left width 3x+1 right width 4x-y. find x and y and area of the rectangle .solution 4x+3=x+6y . y=3x+3÷6 also 4x-y=3x+1.x=y+1

1. 👍
2. 👎
3. 👁
4. ℹ️
5. 🚩
1. Yes that's right. You have to equate the expressions for widths and for the lengths, since left and right widths (and lengths) have the same dimensions.
You may rewrite the equation for y=3x+3÷6 as
y = (3x + 3)/6

And now you have an expression for y, we can substitute it to the other equation you got:
x = y + 1
x = (3x + 3)/6 + 1

And solve for x. After you got the value of x, you can solve for y.

1. 👍
2. 👎
3. ℹ️
4. 🚩

1. 👍
2. 👎
3. ℹ️
4. 🚩
3. I know this was given yearssss ago, but thanks!!!!! It helped a lot today

1. 👍
2. 👎
3. ℹ️
4. 🚩
4. Amazing

1. 👍
2. 👎
3. ℹ️
4. 🚩
5. I don't understand

1. 👍
2. 👎
3. ℹ️
4. 🚩
6. y=3x+3÷6 as y=(3x+3)/6
substitute the equation
x=y+1
x=(3x+3)/6 +1
least i can try

1. 👍
2. 👎
3. ℹ️
4. 🚩
7. Area=L × w=4x+3=x+6y
y=4x_3+3+6
y=3+3+6
y=6+6
y=12.
L×w=4x_y =3x+1
X=4x_3x+1+1
1x=2
x=2

1. 👍
2. 👎
3. ℹ️
4. 🚩
8. I don't understand

1. 👍
2. 👎
3. ℹ️
4. 🚩
9. I did not understand

1. 👍
2. 👎
3. ℹ️
4. 🚩

## Similar Questions

Still need help? You can ask a new question.