If a^2 = 49 and b^2 = 64, which of the following CANNOT be a value of a + b?
F. -15
G. -1
H. 1
J. 15
K. 113
Yes.
Thank you Ms. Sue :).
You're welcome.
To determine which of the given numbers cannot be a value of a + b, we need to find the possible values of a and b from the given equations a^2 = 49 and b^2 = 64.
From the equation a^2 = 49, we can see that a could be either 7 or -7 since (7^2 = 49) and (-7^2 = 49).
Similarly, from the equation b^2 = 64, we can see that b could be either 8 or -8 since (8^2 = 64) and (-8^2 = 64).
Now, let's find all possible values of a + b:
a + b = 7 + 8 = 15
a + b = 7 + (-8) = -1
a + b = -7 + 8 = 1
a + b = -7 + (-8) = -15
By comparing the values we obtained with the given choices, we can conclude that the value -15 cannot be the sum of a + b. Therefore, the answer is (F) -15.