A square which is 7 inches on a side is removed from a triangle which is a base and height of 14 inches. What is the area of the remaining region?
b×h (1/2)
7×14(1/2)
98(1/2
A=49
Perimeter= 7+14+14=35
There appears to be a typo in your problem. So I'm assuming b = h = 14 in.
At = bh/2 = 14*14/2 = 98 in^2 = Area of
triangle.
As = 7^2 = 49 in^2 = Area of the square.
Ar = At-As = 98 - 49 = 49 in^2 = Area
remaining.
To find the area of the remaining region, we first need to find the area of the triangle and then subtract the area of the square.
Step 1: Find the area of the triangle.
The formula for the area of a triangle is: A = (base * height) / 2.
In this case, the base of the triangle is 14 inches and the height is also 14 inches. Plugging these values into the formula, we get:
A_triangle = (14 * 14) / 2
A_triangle = 196 / 2
A_triangle = 98 square inches
Step 2: Find the area of the square.
The area of a square is calculated by squaring the length of one of its sides.
In this case, the length of each side of the square is 7 inches. So, the area of the square is:
A_square = side^2
A_square = 7^2
A_square = 49 square inches
Step 3: Find the area of the remaining region.
To find the area of the remaining region, we subtract the area of the square from the area of the triangle:
A_remaining = A_triangle - A_square
A_remaining = 98 - 49
A_remaining = 49 square inches
Therefore, the area of the remaining region is 49 square inches.