(2y^-1)^2
----------------
(4y)^-2
The answer is supposed to be 64 but I can't seem to get it. Thanks to anyone who can help!
4/y *16y^2=64y
I'm still super confused if anyone else can help I'd love it!
To simplify the expression (2y^-1)^2 / (4y)^-2, we can follow these steps:
Step 1: Deal with negative exponents:
Remember that a negative exponent indicates the reciprocal of the base raised to the positive exponent. So, we can rewrite the expression as follows:
(2/y)^2 / (1/(4y))^2
Step 2: Square each term:
To square a fraction, we square both the numerator and the denominator. Applying this to the expression, we get:
(2^2 / y^2) / (1^2 / (4y)^2)
This simplifies to:
4 / y^2 / (1 / (4^2 * y^2))
Step 3: Evaluate the numbers:
Simplify the numbers in the expression:
4 / y^2 / (1 / (16y^2))
Step 4: Invert and multiply:
We can simplify division by inverting the denominator and multiplying:
4 / y^2 * (16y^2 / 1)
This becomes:
4 * 16y^2 / y^2
Step 5: Simplify:
Finally, we simplify the expression:
64y^2 / y^2
The y^2 terms in the numerator and denominator cancel out, leaving us with:
64
Therefore, the value of the expression (2y^-1)^2 / (4y)^-2 is indeed 64.