Calculate OH and H
pH= 12
How to set this up
pH = -log(H^+). Calculate H^+. Then
(H^+)(OH^-) = Kw = 1E-14
1.0E-14 = [H+] [OH-] = 1E=12 [OH-]
[OH-] = 1E-2 and pOH = 2
To calculate the concentration of hydroxide ions (OH-) and hydrogen ions (H+), you can start by using the formula for pH:
pH = -log[H+]
Given that the pH is 12, you can rearrange the equation to solve for [H+]:
-[H+] = 12
[H+] = 10^(-12)
Since water is a neutral solution, the concentration of hydrogen ions is equal to the concentration of hydroxide ions:
[H+] = [OH-]
Thus, the concentration of hydroxide ions (OH-) can also be calculated as:
[OH-] = 10^(-12)
Therefore, both the concentration of hydroxide ions (OH-) and hydrogen ions (H+) are equal to 10^(-12).