A number cube is rolled 160 times. The number 2 comes up 39 times. what is the experimental probability of rolling a 2? What is the theoretical probability of rolling a 2?

A. 39/160 ; 1/80
b. 1/6 ; 39/160
C. 39/160 ; 1/6
D. 121/160; 1/6

My answer is B. Is this right????

Wasn't there an "experiment" of rolling the dice 160 times? And it came up "2" 39 times

So the experimental prob must be 39/160

The theoretical probability is the actual mathematics one, so the "2" is one of the 6 sides, so the experimental prob is 1/6
looks like C to me

I am pretty sure that C is the answer. Since the theoretical is asking what is the theoretical probability of rolling a 2, it would be 1/6 because there is one 2 on a number cube. For experimental, you rolled the number cube 160 times and 39 of those rolls were 2, so 39/160; 1/6

THESE ARE THE ANSWERS, PROBABILITY TEST 1

Also i only got 13/18 right so i’ll just give you guys those ones, srry.
I also shortened the questions bc I didn’t want to write everything

3. A number cube is rolled 160 times, the number 2 comes up 39 times…

39/160:1/6

4. A spinner is divided into 11 equal sections numbered from 0-10…

6/11

6. Food express is running a special promotion…

3/46

7. A bag contains 4 green, 6 red, 14 orange, 5 brown and 8 blue marbles…

48/1369

8. Each of two urns contains green balls and red balls…

77/180

10. You have five $1 4 $5 six $10 and three $20…

5/51

12. The probability of a basketball player hitting a foul shot is 1/3…

30

13. A true-false test has 8 questions…

1/256

14. Simplify 5!

120

15. Simplify 10p4

5040

16. Simplify 8c5

56

17. You and 5 friends go to a concert…

720

18. You own 7 pairs of jeans…

21

Again, sorry for the missing answers, i dont want to be giving out wrong answers.
Hope this helped

Thank you for providing the answers to the probability test! This will definitely help those who took the test and want to compare their answers, and those who are preparing for a similar test in the future. Great job!

A spinner is divided into 11 equal sections numbered from 0 to 10. You spin the spinner once. What is P(not even)?

A. start fraction 3 over 5 end fraction
B. one-half
C. Start Fraction 5 over 11 End Fraction
D. Start Fraction 6 over 11 End Fraction

The numbers on the spinner that are not even are 1, 3, 5, 7, 9, which represents 5 out of the 11 possible outcomes. Therefore, the probability of getting a number that is not even is:

P(not even) = 5/11

The answer is C.

A bag contains 5 green marbles, 8 red marbles, 11 orange marbles, 7 brown marbles, and 12 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?

A. Start Fraction 20 over 43 End Fraction
B. Start Fraction 40 over 43 End Fraction
C. Start Fraction 20 over 1849 End Fraction
D. Start Fraction 96 over 1849 End Fraction

The probability of selecting a red marble on the first pick is 8/43 (8 red marbles out of 43 total marbles). After replacing the first marble, the probability of selecting a blue marble on the second pick is 12/43 (12 blue marbles out of 43 total marbles).

Since we are looking for the probability of both events happening (red, then blue), we multiply their individual probabilities:

P(red, then blue) = P(red) * P(blue) = (8/43) * (12/43)

Simplifying the expression:

P(red, then blue) = 96/1849

The answer is D.

A bag contains 4 green marbles, 6 red marbles, 14 orange marbles, 5 brown marbles, and 8 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?

ot please help

The probability of selecting a red marble on the first pick, with replacement, is 6/37 (6 red marbles out of 37 total marbles). After replacing the first marble, the probability of selecting a blue marble on the second pick, again with replacement, is 8/37 (8 blue marbles out of 37 total marbles).

Since we are looking for the probability of both events happening (red, then blue), we multiply their individual probabilities:

P(red, then blue) = P(red) * P(blue) = (6/37) * (8/37)

Simplifying the expression:

P(red, then blue) = 48/1369

The answer is therefore not provided, but it can be determined to be 48/1369.

Each of two urns contains green balls and red balls. Urn I contains 8 green balls and 12 red balls. Urn II contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?

bot help please

The probability of drawing a red ball from Urn I is 12/20 (since there are 12 red balls out of 20 total balls). The probability of drawing a red ball from Urn II is 8/13 (since there are 8 red balls out of 13 total balls).

Since we are looking for the probability of both events happening (red from Urn I and red from Urn II), we multiply their individual probabilities:

P(red and red) = P(red from Urn I) * P(red from Urn II) = (12/20) * (8/13)

Simplifying the expression:

P(red and red) = 24/65

Therefore, the probability of drawing a red ball from both urns is 24/65.

You have six $1 bills, eight $5 bills, two $10 bills, and four $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?

bot help please

The probability of choosing a $1 bill on the first draw is 6/20 (since there are six $1 bills out of 20 total bills). After the first bill is drawn, there are 19 bills left, of which two are $10 bills. Therefore, the probability of choosing a $10 bill on the second draw, after the $1 bill has already been selected and not replaced, is 2/19.

Since we are looking for the probability of both events happening (drawing a $1 bill first and then a $10 bill), we multiply their individual probabilities:

P($1, then $10) = P($1) * P($10 after $1) = (6/20) * (2/19)

Simplifying the expression:

P($1, then $10) = 3/190

Therefore, the probability of selecting a $1 bill first and a $10 bill second is 3/190.

A bag contains 6 green marbles and 5 white marbles. You select a marble at random. What are the odds in favor of picking a green marble?

The odds in favor of an event occurring is defined as the ratio of the number of favorable outcomes to the number of unfavorable outcomes. In this case, the favorable outcome is picking a green marble and the unfavorable outcome is picking a white marble.

The number of favorable outcomes (green marbles) is 6, and the number of unfavorable outcomes (white marbles) is 5. Therefore, the odds in favor of picking a green marble are:

Odds in favor of picking a green marble = number of favorable outcomes / number of unfavorable outcomes

Odds in favor of picking a green marble = 6/5

Simplifying the expression:

Odds in favor of picking a green marble = 6:5

Therefore, the odds in favor of picking a green marble are 6 to 5.

Food Express is running a special promotion in which customers can win a free gallon of milk with their food purchase if there is a star on their receipt. So far, 219 of the first 264 customers have not received a star on their receipts. What is the experimental probability of winning a free gallon of milk?

If 219 out of 264 customers did not receive a star on their receipt, that means 45 customers did receive a star on their receipt and are eligible to win a free gallon of milk.

The experimental probability is the number of favorable outcomes (customers who received a star on their receipt) divided by the total number of outcomes (total number of customers):

Experimental probability of winning a free gallon of milk = number of customers with a star on their receipt / total number of customers

Experimental probability of winning a free gallon of milk = 45/264

Simplifying the expression:

Experimental probability of winning a free gallon of milk = 15/88

Therefore, the experimental probability of winning a free gallon of milk is 15/88.

A bag contains 4 green marbles, 6 red marbles, 14 orange marbles, 5 brown marbles, and 8 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?

The probability of selecting a red marble on the first draw, with replacement, is 6/37 (6 red marbles out of 37 total marbles). After replacing the first marble, the probability of selecting a blue marble on the second draw, again with replacement, is 8/37 (8 blue marbles out of 37 total marbles).

Since we are looking for the probability of both events happening (red, then blue), we multiply their individual probabilities:

P(red, then blue) = P(red) * P(blue) = (6/37) * (8/37)

Simplifying the expression:

P(red, then blue) = 48/1369

Therefore, the probability of selecting a red marble and then a blue marble is 48/1369.

Each of two urns contains green balls and red balls. Urn I contains 8 green balls and 12 red balls. Urn II contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?