A sample of potassium hydrogen oxalate, KHC2O4, weighing 0.717 g, was dissolved in water and titrated with 18.47 mL of an NaOH solution. Calculate the molarity of the NaOH solution.

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  1. First, determine the molarity of KHC2O4:

    0.717g*(1 mol/128.12g)=moles of KHC2O4

    18.47 mL=0.01847L

    Molarity of KHC2O4=moles of KHC2O4/0.01847L

    The reaction is a 1 mole to 1 mole reaction. Therefore, moles of KHC2O4=moles of NaOH.

    So, Molarity of KHC2O4=Molarity of NaOH

    ***Answer contains three significant figures.

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  2. 0.185

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