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if 4th term of an arithmetic progression is 3 times the 1st term nd 7th term exceeds twice the third term by 1. find the first term and common difference

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asked by anandita
  1. T4 = 3T1
    T7 = 2T3 + 1

    Now just plug in the values for Tn and you have

    a+3d = 3a
    a+6d = 2(a+2d)+1

    Now just solve for a and d.

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    posted by Steve
  2. a=5 and d=4

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    posted by Anonymous
  3. but the answer is not clear, how the first and common difference is solve

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    posted by Peters

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