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calculus word prob

Two buildings at opposite corners of a parking lot need to be connected by cable that will be buried under ground. It costs $11/ft to lay accross parking lot and $8/ft to lay along the sides. The lot is 300ft by 360 ft rect from pt A to the opposite corner with indents of 60ft off each side. What is cheapest path?

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  1. if the cable goes from A along the 360-ft side for a distance x past the indent at A's corner to y from the indent at B's corner, then the cost will be

    8(60+x) + 11√((300-x)^2+(240-y)^2) + 8(60+y)

    Now, I don't think you have studied multi-variable derivatives, so there must be some other relationship between x and y.

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