chemistry

What is the volume of dry O2 gas at STP, if it had a volume of 5.00 L at 103 kPa and 300 K?

asked by Lee
  1. At STP, T = 0 C or 273 K and P = 1 atm or 101.325 kPa.

    Assuming the gas ideal, we can use the formula:
    P1 * V1 / T1 = P2 * V2 / T2
    where
    P = pressure
    V = volume
    T = absolute temperature (in K)
    subscripts 1 and 2 = initial and final properties respectively

    substituting,
    103 * 5 / 300 = 101.325 * (V2) / 273

    Now solve for V2. Hope this helps~ `u`

    posted by Jai
  2. V2= P1V1T2/P2T1
    = 103*5*273/101.325*300
    =4.63L

    posted by Sasha

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