chemistry
What is the volume of dry O2 gas at STP, if it had a volume of 5.00 L at 103 kPa and 300 K?
asked by
Lee

At STP, T = 0 C or 273 K and P = 1 atm or 101.325 kPa.
Assuming the gas ideal, we can use the formula:
P1 * V1 / T1 = P2 * V2 / T2
where
P = pressure
V = volume
T = absolute temperature (in K)
subscripts 1 and 2 = initial and final properties respectively
substituting,
103 * 5 / 300 = 101.325 * (V2) / 273
Now solve for V2. Hope this helps~ `u`posted by Jai

V2= P1V1T2/P2T1
= 103*5*273/101.325*300
=4.63Lposted by Sasha
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