A 3 ohm, a 5 ohm, and a 4 ohm resistor are connected in series across a battery. The voltage drop across a 3 ohm resistor is 6 V. What is the battery voltage?
24
24
For class 10 board
Class 10 help need
Well, since the voltage drop across the 3 ohm resistor is 6 V, I guess it must have had a rough day and needs some cheering up. But let's not get too charged up about it!
To find the battery voltage, we can use Ohm's law, which states that V = I * R, where V is the voltage across the resistor, I is the current flowing through it, and R is the resistance. So, if we know the voltage drop across the 3 ohm resistor is 6 V, we can find the current flowing through it.
Using Ohm's law, we have 6 V = I * 3 ohm. Solving for I, we get I = 2 A.
Now that we know the current flowing through the 3 ohm resistor is 2 A, we can determine the total resistance of the circuit. Since the resistors are connected in series, we simply add up their individual resistances: 3 ohms + 5 ohms + 4 ohms = 12 ohms.
Knowing the current and the total resistance, we can now find the battery voltage using Ohm's law again. V = I * R, so the battery voltage is 2 A * 12 ohms = 24 V.
So, the battery voltage is 24 volts. It seems like the battery is really positive about powering this circuit!
To find the battery voltage, we need to use Ohm's Law, which states that the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R). In this case, we can use the known voltage drop across the 3 ohm resistor to calculate the current flowing through the circuit.
Given that the voltage drop across the 3 ohm resistor is 6 V, we can use Ohm's Law to find the current flowing through it:
V = I * R
6 V = I * 3 ohm
Rearranging the equation, we have:
I = 6 V / 3 ohm
I = 2 A
We now know that the current flowing through the circuit is 2 A. Since the resistors are connected in series, the same current flows through each resistor in the circuit.
Therefore, the voltage drop across the 5 ohm resistor is:
V = I * R
V = 2 A * 5 ohm
V = 10 V
And the voltage drop across the 4 ohm resistor is:
V = I * R
V = 2 A * 4 ohm
V = 8 V
Finally, to find the battery voltage, we sum up the voltage drops across all the resistors:
Battery Voltage = Voltage drop across 3 ohm + Voltage drop across 5 ohm + Voltage drop across 4 ohm
Battery Voltage = 6 V + 10 V + 8 V
Battery Voltage = 24 V
Therefore, the battery voltage is 24 volts.
3 ohm R. voltage drop is 6v so I = E/R and that I is the I through the circit.
5 ohm frop = IR
4 ohm drop is IR
total voltage is sum of drops across each.